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$\left(\dfrac{a}{b}\right)^{x-1}=\left(\dfrac{b}{a}\right)^{x-3}$, then the value of x is:

1/2
1
2
7/2
Explanation:

Given $\left(\dfrac{a}{b}\right)^{x-1}=\left(\dfrac{b}{a}\right)^{x-3}$

$\Rightarrow \left(\dfrac{a}{b}\right)^{x-1}=\left(\dfrac{a}{b}\right)^{-(x-3)} = \left(\dfrac{a}{b}\right)^{3-x}$

$\Rightarrow$ x - 1 = 3 - x

$\Rightarrow$2x = 4

$\Rightarrow$x = 2.
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