[2.9] Given that 100.48 = x, 100.70 = y and xz = y2 , then t

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Aptitude

TNPSC G4

10th CBSE Maths

Given that 10^0.48 = x, 10^0.70 = y and x^z = y² , then the value of z is close to:

1.45

1.88

2.9

3.7

Explanation:

x^z = y² $\Leftrightarrow$ 10^(0.48z) = 10^{(2 x 0.70)} = 10^1.40

$\Rightarrow$ 0.48z = 1.40

$\Rightarrow$ z =$\dfrac{140}{48}=\dfrac{35}{12}$= 2.9 (approx.)

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