(Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to:
sin 30° = $\dfrac{1}{2}$ sin 60° =$\dfrac{\sqrt{3}}{2}$, cos 30° = $\dfrac{\sqrt{3}}{2}$ and cos 60°= $\dfrac{1}{2}$
Putting these values, we get:
$(\dfrac{1}{2}+\dfrac{1}{2})-(\dfrac{\sqrt{3}}{2}+\dfrac{\sqrt{3}}{2})$
=$ 1 – [\dfrac{(2\sqrt{3})}{2}]$
= 1 – $\sqrt{3}$
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