If cos X = $\dfrac{a}{b}$, then sin X is equal to:
cos X = $\dfrac{a}{b}$
By trigonometry identities, we know that:
$sin^{2}X + cos^{2}X$ = 1
$sin^{2}X$ = $1 – cos^{2}X$ = $1-(a/b)^{2}$
sin X = $\dfrac{\sqrt{(b^{2}-a^{2})}}{b}$
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