21678.Petrol for aviation purpose must contain
straight chain hydrocarbons
olefinic hydrocarbons
aromatic hydrocarbons
highly branched chain hydrocarbons
21679.Which of the following reactions will yield 2, 2–dibromopropane?
CH3–C≡CH + 2HBr →
CH3CH≡CHBr + HBr →
CH≡CH + 2HBr& →
CH3–CH=CH2 + HBr →
21680.HBr reacts with CH2=CH–OCH3 under anhydrous conditions at room temperature to give
CH3CHO and CH3Br
BrCH2CHO and CH3OH
BrCH2–CH2–OCH3
H3C–CHBr–OCH3
21681.When 2–butyne is treated with PdBaSO4 the product formed will be
1–butene
trans–2–butene
cis–2–butene
2–hydroxy butane
21682.The reagent(s) for the following conversion is/are
alcoholic KOH
alcoholic KOH followed by NaNH2
aqueous KOH followed by NaNH2
Zn/CH3OH
21685.The synthesis of 3–octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are
BrCH2CH2CH2CH2CH3 and CH3CH2C≡CH
BrCH2CH2CH3 and CH3CH2CH2C≡CH
BrCH2CH2CH2CH2CH3 and CH3C≡CH
BrCH2CH2CH2CH3 and CH3CH2C≡CH
21686.Alkyl halides react with dialkyl copper reagents to give
alkanes
alkyl copper halides
alkenes
alkenyl halides
21687.The compound formed as a result of oxidation of ethyl benzene by KMnO4 is
benzophenone
acetophenone
benzoic acid
benzyl alcohol
21688.Which of the following compounds will not undergo Friedel–Craft's reaction easily?
Cumene
Xylene
Nitrobenzene
Toluene
21689.Which of the following reagents when heated with ethyl chloride, forms ethylene?
Alcoholic KOH
Zn/HCl
Aqueous KOH
HI
21690.Among the following select the alkane that is expected to have lowest boiling point
Hexane
2–Methylpentane
3–Methylpentane
2, 2–Dimethylbutane
21691.Addition of HBr to propylene in presence of benzoylperoxide, follows :
Carbanion mechanism
Baeyer's rule
Markownikoff's rule
Anti–Markownikoff's rule
21692.The radical
is aromatic because it has
is aromatic because it has
6 p–orbitals and 6 unpaired electrons
7 p–orbitals and 6 unpaired electrons
7 p–orbitals and 7 unpaired electrons
6 p–orbitals and 7 unpaired electrons
21693.Which of the following has highest knocking?
Straight chain olefins
Branched chain olefins
Olefins
Aromatic hydrocarbons
21694.Which one of the following methods is neither meant for the synthesis nor for separation of amines?
Wurtz reaction
Hofmann method
Hinsberg method
Curtius reaction
21695.A petroleum fraction having boiling range 70 – 200°C and containing 6 – 10 carbon atoms per molecule is called
natural gas
gas oil
gasoline
kerosene
21696.The hydrocarbon which can react with sodium in liquid ammonia is
CH3CH2CH2C≡CCH2CH2CH3
CH3CH2C≡CH
CH3CH=CHCH3
CH3CH2C≡CCH2CH3
21697.The order of decreasing ease of abstraction of Hydrogen atoms in the following molecule is
Ha > Hb > Hc
Ha > Hc > Hb
Hb > Ha > Hc
Hc > Hb > Ha