Face value of the bill = Rs. 6000.
Date on which the bill was drawn = July 14 at 5 months. Nominally due date = December 14.
Legally due date = December 17.
Date on which the bill was discounted = October 5.
Unexpired time : Oct. Nov. Dec.
26 + 30 + 17 = 73 days =1/ 5Years
B.D. = S.I. on Rs. 6000 for 1/5 year
= Rs. (6000 x 10 x1/5 x1/100)= Rs. 120.
T.D. = Rs.[(6000 x 10 x1/5)/(100+(10*1/5))]
=Rs.(12000/102)=Rs. 117.64.
B.G. = (B.D.) - (T.D.) = Rs. (120 - 117.64) = Rs. 2.36.
Sol. B.G. = S.I. on T.D.
= Rs.(120 x 15 x 1/2 x 1/100)
= Rs. 9.
(B.D.) - (T.D.) = Rs. 9.
B.D. = Rs. (120 + 9) = Rs. 129.
S.I. on Rs. 1800 = T.D. on Rs. 1872.
P.W. of Rs. 1872 is Rs. 1800.
Rs. 72 is S.I. on Rs. 1800 at 12%.
Time =[(100 x 72)/ (12x1800)]year
1/3year = 4 months.
Sum =[( B.D.*T.D.)/(B.D.-T.D.)]
= Rs.[(120x110)/(120-110)]
= Rs. 1320.
Since B.D. is S.I. on sum due, so S.I. on Rs. 1320 for 8 months is Rs. 120.
Rate =[(100 x120)/( 1320 x 2/3)%
= 13 7/11%.
per annum is Rs. Find the amount of the bill and its present
worth.
Let amount be Rs. x. Then,
x*R*T/100 + (R x T)
=T.D.
=>x * 12*3/ 4/[100+[12*3/4]]
=540
x= 540x109 = Rs.6540
Amount - Rs. 6540. P.W. = Rs. (6540 - 540) - Rs. 6000
Sum due =S.I. xT.D./ S.I. -T.D.
=375x250/375- 250
=Rs.750.
Rate=[100*375/750*3]%=16 2/3%
discount on a certain sum of money for 6 months at 12—% per annum is Rs. 25. Find the sum.
Let the sum be Rs. x. Then,
T.D. = (x*25/2*1/2)/(100+(25/2*1/2))=x*25/4*4/425=x/17
S.I=x*25/2*1/2*1/100=x/16
x/16-x/17=25
=>17x-16x=25*16*17
=>x=6800
Hence, sum due = Rs. 6800.
immediate payment of the half and to defer the payment of the
other half for 2 years. By this arrangement
ins Rs. 40. What is the amount of the bill, if the money be
worth 12-z% ?
Let the sum be Rs. x. Then,
[x/2+(x/2*100)/100+(25/2*2)]-[(x*100)/(100+25/2*1]
=40
=>x/2+2x/5-8x/9=40
=>x=3600
Amount of the bill - Rs. 3600.
Sum =[( B.D.*T.D.)/(B.D.-T.D.)]
= Rs.[(120x110)/(120-110)]
= Rs. 1320.
Since B.D. is S.I. on sum due, so S.I. on Rs. 1320 for 8 months is Rs. 120.
Rate =[(100 x120)/( 1320 x 2/3)%
= 13 7/11%.
T.D. =Ö(P.W.*B.G)
B.G. =(T.D.)2/ P.W.
= Rs.[(110x110)/ 1100]
= Rs. 11.
B.D.= (T.D. + B.G.) = Rs. (110 + 11) = Rs. 121.
Sum = [(B.D.xT.D.)/ (B.D.-T.D.)]
= [(B.D.xT.D.)/B.G.]
T.D./B.G. = Sum/ B.D.
=1650/165
=10/1
Thus, if B.G. is Re 1, T.D. = Rs. 10.
If B.D.is Rs. ll, T.D.=Rs. 10.
If B.D. is Rs. 165, T.D. = Rs. [(10/11)xl65]
=Rs.150
And, B.G. = Rs. (165 - 150) = Rs. 15.
Let amount of the bill = Rs.100
Money deducted =Rs.10
Money received by the holder of the bill = Rs.100-10 = Rs.90
SI on Rs.90 for 10 months = Rs.10
Rate =[(100*10)/(90*10/12)%=13 1/3%
Let T.D. be Re. 1.
Then, B.D. = Rs.$ \dfrac{11}{10} $= Rs. 1.10. |
$\therefore$ Sum = Rs.$ \left(\dfrac{1.10 \times 1}{1.10 - 1} \right) $= Rs.$ \left(\dfrac{110}{10} \right) $= Rs. 11. |
$\therefore$ S.I. on Rs. 11 for 2 years is Rs. 1.10
$\therefore$ Rate =$ \left(\dfrac{100 \times 1.10}{11 \times 2} \right) $%= 5%. |
$BG =\dfrac{{TD}^2 }{PW} = \dfrac{{340}^2 }{3400}$
$= \dfrac{340 \times 340 }{3400} = \dfrac{340}{10} = Rs.34$
$BG = \dfrac{{TD}^2 }{PW} = \dfrac{{72}^2}{1296}$
= $\dfrac{72 \times 72}{1296} = \dfrac{12 \times 12}{36} = \dfrac{12}{3} =Rs.4$
BG = BD - TD
=> 4 = BD - 72
=> BD = 72 + 4 = Rs. 76
BG = Rs. 360
T = 3 years
R = 12%
$TD =\dfrac{BG\times 100}{TR}$
$= \dfrac{360 \times 100}{3 \times 12} = Rs. 1000$
BG = BD - TD
=> BD = BG + TD = 360 + 1000 = Rs. 1360
T.D =$ \frac{B.D\times100}{100\left(R\times T\right)}$
= Rs.$\left[\frac{420\times100}{100+\left(15\times1/3\right)}\right]$
=$\left[\frac{420\times100}{105}\right]$
= Rs. 400.
T.D. =$ \dfrac{B.G. \times 100}{R \times T} $= Rs.$ \left(\dfrac{6 \times 100}{12 \times 1} \right) $= Rs. 50. |
T.D. = $ \sqrt{P.W. \times B.G.} $ = $ \sqrt{576 \times 16} $ = 96.
B.G. =$ \dfrac{(T.D.)^2}{P.W.} $= Rs.$ \left(\dfrac{160 \times 160}{1600} \right) $= Rs. 16. |