[\dfrac{11}{120}] If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectivel

For Competitive Exams

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

$ \dfrac{55}{601} $

$ \dfrac{601}{55} $

$ \dfrac{11}{120} $

$ \dfrac{120}{11} $

Explanation:

Let the numbers be $ a $ and $ b $.

Then, $ a $ + $ b $ = 55 and ab = 5 x 120 = 600.

$\therefore$ The required sum =$ \dfrac{1}{a} $+$ \dfrac{1}{b} $=$ \dfrac{a + b}{ab} $=$ \dfrac{55}{600} $=$ \dfrac{11}{120} $

Additional Questions

Which of the following has the most number of divisors?	Answer
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:	Answer
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:	Answer
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?	Answer
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:	Answer
What is the HCF of 2.04, 0.24 and 0.8 ?	Answer
The G.C.D. of 1.08, 0.36 and 0.9 is:	Answer
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:	Answer
The H.C.F of two 9/10,12/25,18/35 and 21/40 is:	Answer
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:	Answer

Share with Friends