The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
L.C.M. of 5, 6, 7, 8 = 840.
$\therefore$ Required number is of the form 840 k + 3
Least value of $ k $ for which [840$ k $ + 3] is divisible by 9 is $ k $ = 2.
$\therefore$ Required number = $\left(840 \times 2 + 3\right)$ = 1683.
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Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is: |
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What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder? |
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The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: |
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What is the HCF of 2.04, 0.24 and 0.8 ? |
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The G.C.D. of 1.08, 0.36 and 0.9 is: |
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The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: |
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The H.C.F of two 9/10,12/25,18/35 and 21/40 is: |
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If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: |
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Which of the following has the most number of divisors? |
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The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: |
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