[85] Three numbers which are co-prime to each other are such that the product of the first two is 551 and

For Competitive Exams

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number =$ \left(\dfrac{551}{29} \right) $= 19; Third number =$ \left(\dfrac{1073}{29} \right) $= 37.

$\therefore$ Required sum = $\left(19 + 29 + 37\right)$ = 85.

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