What is the least number which when divided by 8, 12, 15 and 20 leaves in each case a remainder of 5 ?
LCM of 8, 12, 15 and 20 = 120
Required Number = 120 + 5 = 125
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The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: |
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Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is: |
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Which of the following fraction is the largest ? |
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Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: |
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The H.C.F of two 9/10,12/25,18/35 and 21/40 is: |
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If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: |
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Which of the following has the most number of divisors? |
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The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is: |
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The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: |
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What is the least number which when divided by 8, 12, 15 and 20 leaves in each case a remainder of 5 ? |
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