[\dfrac {7}{8} > \dfrac...] Arrange the following fractions \dfrac {1}{2}, \dfrac {3}{4}, \dfrac {7}{8}, \dfrac {5}{12}

For Competitive Exams

Arrange the following fractions $\dfrac {1}{2}$, $\dfrac {3}{4}$, $\dfrac {7}{8}$, $\dfrac {5}{12}$ in descending order

$\dfrac {7}{8}$ > $\dfrac {1}{2}$ > $\dfrac {5}{12}$ > $\dfrac {3}{4}$

$\dfrac {7}{8}$ > $\dfrac {3}{4}$ > $\dfrac {1}{2}$ > $\dfrac {5}{12}$

Explanation:

Now, $\dfrac {1}{2}$ = 0.5, $\dfrac {3}{4}$ = 0.75, $\dfrac {7}{8}$ = 0.875 , $\dfrac {5}{12}$ = 0.416...

Since, 0.875 > 0.75 > 0.5 > 0.416... . So $\dfrac {7}{8}$ > $\dfrac {3}{4}$ > $\dfrac {1}{2}$ > $\dfrac {5}{12}$

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