If $log_{5} (x^2 + x) - log_{5} (x + 1)$ = 2, then the value of x is
$log_{5}\left(\dfrac{x^2+x}{x+1}\right)$=$log_{5}25$
=>$\left(\dfrac{x^2+x}{x+1}\right)$=25
=>$x^2-24x-25$=0
=>$(x-25)(x+1)$=0
=>x=25
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