According to the question, In 20 kg there was 18 kg water and the rest 2 kg was pure grapes which will never reduce.
So, when the grapes get dried and there is only 20% water then rest 80 kg will be pure grapes which is 2 kg.
Let x be total quantity then -----x $\times$ 80/100 = 2.
On solving, we get x=2.5
Hence, the required weight of grapes = 2.5 kg.
According to the question,
Aunt/uncle=5x/6x and Suzanne/beard = 5y/6y.
So, Aunt + Suzanne = 5x + 5y
Before 5 years= 5(x + y) - 10 = 60x + y = 14.
Again,
After 5 years, uncle + beard = 6(x+y) + 5 + 5 = 6(14) + 10 = 94.
Given, Reduction in wage is =15:11
and, Increment in wage is = 22:25
Total wages ratio = reduction workers ratio* increment wage ratio.
=> (15/11) $\times$ (22/25) = 6/5.
Hence, the total wages ratio = 6/5.
Let the principal be 100.
Then, Amount = 200, SI=100
SI=p $\times$ n $\times$ r/100.
=> r=100 $\times$ si/p $\times$ n.
=> r=100 $\times$ 100/100 $\times$ 5.
=> r=20.
Suppose each tv costs 100rs a sales were 100 in number, therefore revenue is 10000.
After hiking price by 15% each tv costs 115rs due to sales decreased by 15% which are 85 in number,
therefore revenue now, is 9775.
Therefore, revenue in % = (9775/1000) $\times$ 100 => 97.75%
Initial revenue percent is 100 => 100-97.75 = 2.25% decrease.
The of given amount = LCM (16,18,20,25) =3600
And, he left with Rs. 4.
Hence, the required amount is 3600 + 4 = 3604.
Let dimensions of tank are x $\times$ y $\times$ z = xyz.
So xyz can hold k liters of water.
Now dimensions are doubled i.e 2x $\times$ 2y $\times$ 2z=8xyz
As xyz holds k liters, so 8xyz will hold 8 $\times$ k = 8k liters of water.
Volume of cylinder = h $\times$ Pi $\times r^2$
Volume of sphere= (4/3) $\times$ pi$\times r^3$.
=> (4/3) $\times$ pi $\times r^3$ = h $\times$ Pi $\times r^2 $
=> (4/3) $\times$ r = h
=> r= h $\times$ 3/4.
For the roots to be equal, $b^2$-4ac = 0 is the condition.
Here, from the equation,
a=2k, b=5k and c=2
=> $(5k)^2$-4(2k) (2) =0
=> $25k^2$-16k=0
=> k(25k-16) =0
=> k=16/25.
A sample of 22 liter containing 90% water will have 10% milk i.e. 2.2-liter milk.
2.2-liter milk in a mixture of 11% milk means total mixture is 100 $\times$ 2.2/11= 20 liter.
So, 2-liter water should be added in 20-liter mixture of 89% water to make it 22-liter mixture having 90% water.
Series Completion:
4, 7, 10, 10, 16, 13,?The given sequence is a combination of two series:
(I) 4, 10,16,? and (II) 7, 10, 13
So, the next term of the series I is 16 + 6 = 22.
The given code is reverse of the given word.
C.M + K - R
The candidates, Proloy Saha, does not satisfy Condition B. However, he is Ph.D. in Psychology. Hence, his case should be referred to Deputy Director.
We have 60% of 50 = (60/100 $\times$ 50) = 30.
Therefore, Required number
= No. of students scoring 30 and above marks in Physics
= 32.