Take options and check. If 10 are correct, his score is 10 x 8 = 80. But 16 are wrong. So total negative marking is 16 x 5 = 80. So final score is zero.
(5C0×11C11)+(5C1×11C10)+(5C2×11C9)+(5C3×11C8)=2256
Take a = 1, b = 2, c = 3, d = 4. option A is clearly true.
Just check the options. If she bought 10 white sharpeners at Rs.6 per piece, She has spent Rs.60 already.
And with the remaining Rs.40, she bought 8 brown sharpeners at 40/8 = Rs.5 which is Rs.1 less than White sharpener.
Let us assume right most two squares are a , b
Then Sum of all the squares = 18 x 4 + a + b .......... (1)
Also Sum of the squares before 7 = 18
Sum of the squares between 7, x = 18
and sum of the squares between x , 8 = 18
So Sum of the 14 squares = 18 + 7 + 18 + x + 18 + 8 + a + b...... (2)
Equating 1 and 2 we get x = 3
The number of ways of rolling a dice where no two numbers probability that no one rolls the same number = 6 x 5 x 4 x 3
Now total possibilities of rolling a dice = 64
The probability that a no one gets the same number = 6 $\times$ 5 $\times$ 4$\times$ 364=518
So the probability that at least two people gets same number = 1/518=13/18
Explanation: Simple one. Let the total work to be done is 48 meters. Now Jake can dig 3 mts, Paul can dig 2 mts a day. Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts. So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.
This question can be solved easily by going through options.
A. White sharpener total cost: Rs.5 x 10 = Rs.50. Brown sharpeners cost = Rs.4 x 8 = 32. Total cost is only Rs.82. Wrong option.
B. White sharpener total cost: Rs.6 x 10 = Rs.60. Brown sharpeners cost = Rs.5 x 8 = 40. Total cost is Rs.100. Correct option.
Check options. Sum of the squares should be equal to 109. Only Options B and D satisfying. When we subtract 495, only 863 becomes 368.
Let the money with Mark and John are M and J respectively.
Now
M + J/2 = 75
M/3 + J = 75
Solving we get M = 45, and J = 60.
Faulty spring balance reads 0.9 kg for a kg" means that she sells 1 kg for the price of 0.9 kgs, so she looses
10% of the price because of the faulty spring balance. She looses another 10% because of the discount.So, she actually sells 1 kg for 3 $\times$ 0.9 $\times$ 0.9=2.43 and since at that price she made neither a profit nor a loss, then Eesha purchase the wheat from the wholesaler for $2.43.
Let x be the price of the orange.
We can write that 20x is the money that he has with him.
If the price of orange is reduced by 2 rupees, he can buy 30 of them.
That means we can write:
30(x-2) = 20x
30x - 60 = 20x
30x - 20x = 60
10x = 60
x = 6
So, he has 120 rupees (20x) and can buy 30 if the price becomes 4 per orange. The solution checks out.
We solve this problem by taking numbers. Let the shortest of Braves is 4 feet. Then tallest of Aziecs is less than 4. So let it be 3 feet.
A -> 2 - 3
B -> 4 - 6
C -> 1 - 7
From the above we can safely conclude X is correct. but Y cannot be determined.
Class A average is 20. And their range is 18 to 22
Class B average is 25. And their range is 23 to 31
Class A average is 30. And their range is 26 to 33
If 5 students transferred from A to B, As average cannot be determined but Bs average comes down as the highest score of A is less than lowest score of B.
If 5 students transferred from B to C, Cs average cannot be determined the Bs range fo marks and Cs range
of marks are overlapping.
40,000(3/4)3=16875
Let the work be 60 units. If venky worked for 3 days, and the remaining days of work be x days, total days to complete the work be x + 3 days.
Now Capacities of Rajiv is 60/10 = 6, Venky is 5, Ravi is 4.
(6 + 5 + 4) 2 + (5 + 4) (x - 3) + 5 x 3 = 60.
Solving we get x = 4. So total days to complete the work is 7 days.
He works for 8 days and takes rest on the 9th day. So On the 12th rest day, there are 9 x 12 = 108 days passed.
Number of odd days = (108 - 1) / 7 = 107 / 7 = 2. So the 12th rest day is wednesday.
If N=ap $\times$ bq $\times$ cr.... then the number of factors of N = (p+1)(q+1)(r+1) ....
600 = 23 $\times$ 3 $\times$ 52
So number of factors of 600 = (3+1)(1+1)(2+1) = 24
Use formula n(n+1)(2n+1)6