Let, M.P of the television = x.
According to the question, C.P. = x - 20x/100
=> 2400 = (100x-20x)/100
=> 2400 $\times$ 100 = 80x
$\therefore$ Market Price i.e. x = (2400 $\times$ 100)/80 = Rs. 3000
Now S.P = MP - Discount
= 3000 - 480. (because discount in rs = (16/ 100) $\times$ 3000 = 480)
= 2520.
profit = 2520 - 2400 = 120 i.e. 5%
Let `T` be the total age of 5 girls.
Then, T/5 = 11.
=> T = 55.
Given, Age of the Oldest girl = 15.
Then, Total age of other 4 girls will be 55-15=40.
So, Avg. of other 4 girls 40/4 = 10.
Let x be the required number.
Then, According to the question,
=> (5+x)/(12+x) = 3/4
=> 20 + 4x = 36 + 3x.
=> x = 16.
Let the age of son = S years and the age of father = F years.
According to the question,
=> F = 3 $\times$ S.
=> F = 3S.
After 5 years,
=> (F+5) = 2.5 $\times$ (S+5).
=> 3S + 5 = 2.5S + 12.5 [put F=3S]
=> 0.5S = 7.5
=> S = 15
Hence, the age of son = 15 years.
According to the question,
Boys: Girls => 5x: 6x
Total no. of students including boys and girls = 5x + 6x = 11x
25% of boys => 5x $\times$ 25/100 = 5x/4
20% of girls => 6x $\times$ 20/100 =6x/5
No. of students who are getting scholarship => 5x/4 + 6x/5 = 49x/20
No. of students who are not getting scholarship = 11x - 49x/20 = 171x/20
Hence, the percentage of students not getting scholarship => 171x/20/11x $\times$ 100
=> 100 $\times$ 171x/220x.
=> 77.7% = 78%(approx.).
According to the question,
A+B`s 1-day work = 1/30.
A+B`s 20 days work = 20 $\times$ 1/30 = 2/3.
Remaining work left = 1-2/3 = 1/3.
A does 1/3 work in ---> 20 days.
A does 1 work in ---> x days.
=> x = 3 $\times$ 20 = 60 days.
A will take 60 days to complete the whole work.
So, A`s 1-day work = 1/60.
Therefore, B`s 1-day work = (A+B)`s 1-day work - A`s 1-day work.
=> 1/30 - 1/60 = 1/60
So, B`s 1-day work = 1/60
Hence, B will complete the entire work alone in 60 days.
SI for 3 years = 2600-2240 = 360
SI for 2 year 360/3 $\times$ 2 = 240
principal = 2240 - 240 = 2000.
Let the rate along the current be x kmph.
Then, (x + 4.5)/2 = 6.
$\therefore$ x = 7.5.
Let Saiji`s share is x.
Then, Annie`s share = x/2 and Maya`s share = x/4.
Therefore, Maya: Annie: Saiji = x/4: x/2: x = 1: 2: 4.
Therefore, Saiji`s share = Rs. 900 $\times$ 4/9 = Rs.400.
Let, length= x meters and breadth= y meters
Then xy=60 and $(x^2+y^2) $+ x= 5
Therefore, x=60 and $(x^2 + y^2)$ = $(5y-x) ^2$.
Or xy=60 and $24y^2$-10xy = 0.
Therefore, $24y^2$ - 10 $\times$ 60 = 0 or
=> $y^2$ = 25
=> y = 5.
Therefore, x= (60/5) m= 12m.
So, length of the carpet = 12m
Robert Bosch Logical Reasoning Test
Analogy:Apostate: Religion ::? ?
Apostate -- a person who betrays or not faith in his/her religion
Traitor -- a person who betrays his country.
Embarrassed: humiliated :: frightened:?
If someone has been humiliated, they have been greatly embarrassed. If someone is terrified, they are extremely frightened.
Statement:
No trunks are ivories.
No toes are trunks
Conclusion:
(1) all toes are ivories
(2) some trunks are ivories
a) No trunks are ivories. (Universal Negative-UN)and,
b) b) No toes are trunks. (Universal Negative-UN)
UN + UN will not give any conclusion.
If COMPLETED is coded as MOCELPDET, then DIRECTION will be coded as:
In given word, word is divided into three parts like
COM+PLE+TED, then these parts are written in reverse order as MOC+ELP+DET
So DIRECTION will be DIR+ECT+ION, which will be RIDTCENOI.
In a certain code language COMPUTER is written as RFUVQNPC. How will MEDICINE be written in that code language?
There are 8 letters in the word.
The coded word can be obtained by taking the immediately following letters of word, expect the first and the last letters of the given word but in the reverse order. That means, in the coded form the first and the last letters have been interchanged while the remaining letters are coded by taking their immediate next letters in the reverse order.
How many students are enrolled in Sastri`s Quant class?
(I). If 3 more students sign up for the class and no one drops out, more than 35 students will have enrolled in the class.
(II). If 4 students drop out of the class and no more sign-up, fewer than 30 students will have enrolled in the class.
Statement I alone is not sufficient, but I does imply that at least 33 students are enrolled in the class. Statement II alone is not sufficient, but II does imply that no more than 33 students are enrolled in the class.
Although neither statement alone is sufficient, the two statements taken together are sufficient to answer the question that the number of students enrolled in the class is 33.
Question: Who among P, Q, R, S and T is the lightest?
(I) R is heavier than Q and T but lighter than S.
(II) S is not the heaviest.
From I, we have: R>Q, R>T, S>R i.e. S>R>Q>T or S>R>T>Q.
From II, S is not the heaviest. So, P is the heaviest.
Thus, we have: P > S > R > Q > T or P > S > R > T > Q.
Hence, either T or Q is the lightest.
Rita drives to the North of her place of stay at A and after traveling 25 km, finds that she has driven in the wrong direction she then turns to her right and travels 2 km and then she again turns to the right and drives straight another 25 km. How much distance has she now to cover to go back to the starting point
22, 21, 23, 22, 24, 23, ___?
In this simple alternating subtraction and addition series; 1 is subtracted, then 2 is added, and so on.
Please look carefully at the series, its pattern is,
-1, +2, -1, +2, -1, so next will be +2
23+2 = 25
8, 43, 11, 41, __, 39, 17
This is a simple alternating addition and subtraction series. The first series begins with 8 and adds 3; the second begins with 43 and subtracts 2.