Page : 11 - Aptitude Area Practice Q&A-Easy

10914.How many paying stones, each measuring 2 1/2 m $\times$ 2 m are required to pave a rectangular court yard 30 m long and 16 1/2 m board?

99

90

95

100

Explanation:

30 $\times\frac{33}{2}$ =$\dfrac{5}{2}$ $\times$ 2 $\times x$ => x = 99

10915.Find the number of square tiles to cover the floor of a room measuring 4 m $\times$ 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?

425

476

450

350

Explanation:

3 1/2 $\times$ 8 1/2 = 1/4 $\times$ 1/4 $\times x$ => x = 476

10916.A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?

Rs.700

Rs.1200

Rs.1400

Rs.1500

Explanation:

l $\times$ 30 = 1200 $\rightarrow$ l = 40

$\sqrt{40^2+30^2}$ = 50

40 + 30 + 50 = 120

120 $\times$ 10 = 1200

10917.The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?

31 m

32 m

16 m

20 m

Explanation:

A/8 = 8 $\times$ 8 => A = 8 $\times$ 8 $\times$ 8

x $\times 2x$ = 8 $\times$ 8 $\times$ 8

x = 16 => 2x = 32

10918.The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?

Rs.1014

Rs.1140

Rs.999

Rs.1085

Explanation:

$a^2$ = 3136 => a = 56

56 $\times$ 4 $\times$ 3 = 672 - 6 = 666 $\times$ 1.5 = 999

10919.The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?

432 sq m

356 sq m

452 sq m

428 sq m

Explanation:

$2\left(3x + x\right)$ = 96

l = 36 b = 12

lb = 36 $\times$ 12 = 432

10920.A rectangular grass field is 75 m $\times$ 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?

675, Rs.1350

575, Rs.1350

1350, Rs.675

None

Explanation:

Area =$\left (l + b +2d\right)$ 2d

= (75 + 55 +2.5 $\times$ 2) 2$\times$2.5 => 675

675 $\times$ 2 = Rs.1350

10921.A rectangular lawn of dimensions 80 m $\times$ 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?

Rs.3600

Rs.3700

Rs.3800

Rs.3900

Explanation:

Area = $\left(l + b - d\right)$ d

(80 + 60 - 10)10 => 1300 $m^2$

1300 $\times$ 3 = Rs.3900

10922.The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?

Remains same

5% decrease

5% increase

10% increase

Explanation:

100 $\times$ 100 = 10000

125 $\times$ 80 = 10000

No change

10923.The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?

529 sq m

240 sq m

260 sq m

480 sq m

Explanation:

$26^2$ � $10^2$ = $24^2$

$d_{1}$ = 20 $d_{2}$ = 48

1/2 $\times$ 20 $\times$ 48 = 480

10924.The diagonals of a rhombus are 15 cm and 20 cm. Find its area?

120 sq m

300 sq m

150 sq m

480 sq m

Explanation:

1/2 $\times$ 15 $\times$ 20 = 150

10925.The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?

260 $cm^2$

240 $cm^2$

280 $cm^2$

220 $cm^2$

Explanation:

4a = 68 => a = 17

172 - 82 = 152

1/2 $\times$ 16 $\times$ 30 = 240

10926.The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?

8 m

10 m

6 m

12 m

Explanation:

2x $\times$ x = 128 => x= 8

10927.The side of a square is increased by 25% then how much % does its area increases?

52.65

56.25

50.75

42.75

Explanation:

a = 100 $a^2$ = 10000

a = 125 $a^2$ = 15625

----------------

10000 --------- 5625

100 -------? => 56.25 %

10928.The cross-section of a cannel is a trapezium in shape. If the cannel is 10 m wide at the top and 6 m wide at the bottom and the area of cross-section is 640 sq m, the depth of cannel is?

20 m

60 m

40 m

80 m

Explanation:

1/2 $\times$ d (10 + 6) = 640

d = 80

10929.The radius of a circle is increased by 1%. Find how much % does its area increases?

1.01%

5.01%

3.01%

2.01%

Explanation:

r = 100 r = 101

$r^2$ = 10000 $r^2$ = 10201

10000 ---- 201

100 ---- ? => 2.01%

10930.Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?

120 sq m

150 sq m

110 sq m

300 sq m

Explanation:

1/2 $\times$ 20(9 + 6) = 150 $cm^2$

10931.Find the area of circle whose radius is 7m?

124 sq m

154 sq m

145 sq m

167 sq m

Explanation:

22/7 $\times$ 7 $\times$ 7 = 154

10932.If the area of circle is 616 sq cm then its circumference?

78 m

88 m

75 m

70 m

Explanation:

22/7 $r^2$ = 616 => r = 14

2 $\times$ 22/7 $\times$ 14 = 88

10933.Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?

Rs.150

Rs.132

Rs.100

Rs.125

Explanation:

2 $\times$ 22/7 $\times$ 14 = 88

88 $\times$ 1 1/2 = Rs.132

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