If (a – b) is 9 more than (c + d) and (a + b) is 3 less than (c – d), then (a – c) is:
1266.When simplified, the product (1 – 1/2) (1 – 1/3) (1 – 1/4)…… (1 – 1/n) gives:
3
None of these
1/n
2/n
If a * b = 2a – 3b + ab, then 5 * 7 + 7 * 5 is equal to:
1269.If a, b, c are integers; a² + b² = 45 and b² + c² = 40, then the values of a, b and c respectively are :
x is greater than y
x is greater than y only if a < 1
2, 6, 3
3, 2, 6
1270.A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1206. Find the number to be multiplied.
5, 4, 3
None of these
130
132
1271.In a garden, there are 12 rows and 14 columns of mango trees. The distance between two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
134
136
20m
22m
1272.In a group of donkeys and pigs, the numbers of legs are 16 more than twice the number of heads. The number of donkeys is
24m
26m
6
8
1274.An enterprising businessman earns an income of Re 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 20th day of business, he earns an income of:
30
35
Rs 2^19
Rs 220
In an examination, a student scores 4 marks for every correct answer and loses 1mark for every wrong answer. If he attempts all 90 questions and secures 140 marks, the number of questions he attempts correctly, is:
1276.Anitha had 80 currency notes in all, some of which are of Rs 95 denomination and the remaining of Rs 45 denomination. The total amount of all these currency notes was Rs. 4000. How much amount (in Rs) did she have in the denomination of Rs 45?
42
46
3500
72
1277.How many pieces of 0.85 metres can be cut from a rod 42.5 metres long?
2000
None of these
30
40
The ratio between two numbers is 4:5 and their sum is 540. The greater of the two numbers is?
1328.How many times do the hands of a clock coincide in a day?
20
21
22
24
Explanation:
The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they
Coincide only once, i.e., at 12 oclock).
AM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
PM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
The hands overlap about every 65 minutes, not every 60 minutes.
The hands coincide 22 times in a day.
The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they
Coincide only once, i.e., at 12 oclock).
AM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
PM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
The hands overlap about every 65 minutes, not every 60 minutes.
The hands coincide 22 times in a day.
1329.A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min.48 sec fast at 2 p.m. on the following Monday. When was it correct?
2 p.m. on Tuesday
2 p.m. on Wednesday
3 p.m. on Thursday
1 p.m. on Friday
Explanation:
Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days
2 hours = 170 hours.
The watch gains 2 + 4
4
min.
or
34
min. in 170 hrs.
5 5
Now,
34
min. are gained in 170 hrs.
5
2 min. are gained in 170 x
5
x 2
hrs
= 50 hrs.
34
Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.
on Wednesday.
Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days
2 hours = 170 hours.
The watch gains 2 + 4
4
min.
or
34
min. in 170 hrs.
5 5
Now,
34
min. are gained in 170 hrs.
5
2 min. are gained in 170 x
5
x 2
hrs
= 50 hrs.
34
Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.
on Wednesday.
1375.The ratio between the speeds of the A& B is 2:3 an therefore A takes 10 min more
than the time taken by B to reach the destination. If A had walked at double the speed ,he
would have covered the distance in ?
than the time taken by B to reach the destination. If A had walked at double the speed ,he
would have covered the distance in ?
15mins
14mins
10mins
None of these
Explanation:
Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)
Ratio of speed = 2:3
Ratio of time = 3:2
A takes 10 min more
3x-2x = 10 min
A time=30 min
A covers the distance in 30 min , if its speed is x
He will cover the same distance in 15 min, if its speed
doubles (i.e 2x)
1421.The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle?
18 cm
16 cm
40 cm
20 cm
Explanation:
Let breadth = $x$ cm
Then length = 2$x$ cm
Area = lb = $x \times 2x$ = 2$x$2
New length = $\left(2x - 5\right)$
New breadth =$\left (x + 5\right)$
New Area = lb = $\left(2x - 5\right)\left(x + 5\right)$
But given that new area = initial area + 75 sq.cm.
=> $\left(2x - 5\right)\left(x + 5\right)$ = 2$x$2 + 75
=> 2$x$2 + 10$x$ - 5$x$ - 25 = 2$x$2 + 75
=> 5$x$ - 25 = 75
=> 5$x$ = 75 + 25 = 100
=> $x$ = $\dfrac{100}{5}$ = 20 cm
Length = 2$x$ = 2 × 20 = 40cm
1422.The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:
15360
153600
30720
307200
Explanation:
| Perimeter = Distance covered in 8 min. =$ \left(\dfrac{12000}{60} \times 8\right) $m = 1600 m. |
Let length = 3$x$ metres and breadth = 2$x$ metres.
Then, 2$\left(3x + 2x\right) = 1600 $ or $x$ = 160.
$\therefore$ Length = 480 m and Breadth = 320 m.
$\therefore Area = (480 \times 320)$ m2 = 153600 m2.
1423.The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
25% increase
50% increase
50% decrease
75% decrease
Explanation:
Let original length = $x$ and original breadth = $y$.
Original area = $x$$y$.
| New length =$ \dfrac{x}{2} $. |
New breadth = 3y.
| New area =$ \left(\dfrac{x}{2} \times 3y\right) $=$ \dfrac{3}{2} xy $. |
| $\therefore$ Increase % =$ \left(\dfrac{1}{2} xy \times\dfrac{1}{xy} \times 100\right) $%= 50%. |