Tick the correct answer and justify :
ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is
Given, ΔABC and ΔBDE are two equilateral triangle. D is the midpoint of BC.
∴ BD = DC = $\dfrac{1}{2BC}$
Let each side of triangle is 2a.
As, ΔABC ~ ΔBDE
$\dfrac{ Area(ΔABC)}{Area(ΔBDE)} = \dfrac{AB^2}{BD^2} = \dfrac{(2a)^2}{(a)^2} = \dfrac{4a^2}{a^2} = \dfrac{4}{1} = 4:1$
Hence, the correct answer is (C).