9584.Who remarked "The light has gone out of our lives and there is darkness everywhere"?
Vallabai Patel
Dr. Rajendra Prasad
Mount Batten
Jawallarlal Nehru
9586.Who chaired the first session of the Indian National Congress held at Bombay?
Madan Mohan Malavya
W.C. Banerjee
Pherozeshah Mehta
Surendranath Banerjee
9588.In India the organisation which was responsible for self-sufficiency in food production was
CSIR
ICAR
ISRO
ICMR
9590.As explained by Robert Malthus, Population increases in the
Proportionate ratio
Geometric ratio
Arithmetic ratio
Smaller ratio
9592.Which plan was implemented after the Annual Plans of 1966– 69?
Second Five Year Plan
Fifth Five Year Plan
Third Five Year Plan
Fourth Five Year Plan
9594."Bachpan Bachao Andolan" is an organisation that fights against
Child labour
Bonded labour
Child marriage
Poverty
9596.The base of a triangle is four times its height and its area is 50 $m^{2}$. The length of the base is
10 m
15 m
20 m
25 m
Explanation:
From given question we know that
b=4h----->(1)
Area of triangle=1/2 b*h=50m^2
b*h=50*2
b*h=100----->(2)
substitute b=4h in equation(2)
then,4h*h=100
h*h=100/4
h*h=25
h=5 substitute in (1)
b=4h
b=4*5
therefore base b=20m
From given question we know that
b=4h----->(1)
Area of triangle=1/2 b*h=50m^2
b*h=50*2
b*h=100----->(2)
substitute b=4h in equation(2)
then,4h*h=100
h*h=100/4
h*h=25
h=5 substitute in (1)
b=4h
b=4*5
therefore base b=20m
9598.A can do a piece of work in 20 days and B can do it in 25 days. Both of them finished the
work and earned Rs. 3,600. Then As share is
work and earned Rs. 3,600. Then As share is
Rs. 1,600
Rs. 2,000
Rs. 3,000
Rs. 3,100
Explanation:
A can do a work in 20 days
B can do the same work in 25 days
therefore, ratio=A's 1 day work:B's 1 day work
A:B=$\dfrac{1}{20}:\dfrac{1}{25}$
=$\dfrac{1}{4}:\dfrac{1}{5}$
=5:4
then,A's share=$Rs.\dfrac{5}{9} \times 600$
=Rs.2,000
A can do a work in 20 days
B can do the same work in 25 days
therefore, ratio=A's 1 day work:B's 1 day work
A:B=$\dfrac{1}{20}:\dfrac{1}{25}$
=$\dfrac{1}{4}:\dfrac{1}{5}$
=5:4
then,A's share=$Rs.\dfrac{5}{9} \times 600$
=Rs.2,000
9600.If $\left(\dfrac{7}{12}\right)^{-4} \times \left(\dfrac{7}{12}\right)^{3x}$ = $\left(\dfrac{5}{12}\right)^{5}$ then the value of x is
- 1
1
2
3
Explanation:
Formula:
$a^{m}\times a^{n}=a^{m+n}$
$=>(\dfrac{7}{12})^{-4+3x}=(\dfrac{7}{12})^{5}$
=>-4+3x=5
3x=5+4
3x=9
x=3
Formula:
$a^{m}\times a^{n}=a^{m+n}$
$=>(\dfrac{7}{12})^{-4+3x}=(\dfrac{7}{12})^{5}$
=>-4+3x=5
3x=5+4
3x=9
x=3
9602.If 22 men can build a wall of 110 meters in 10 days. The length of a similar wall built by 30 mem in 6 days is
100 mts
90 mts
80 mts
70 mts
Explanation:
$\dfrac{M_{1}D_{1}}{W_{1}}=\dfrac{M_{2}D_{2}}{W_{2}}$
$\dfrac{22\times 10}{110}=\dfrac{30\times 6}{W_{2}}$
$W_{2}=\dfrac{30\times 6\times 110}{22\times 10}$
$W_{2}=90mts$
$\dfrac{M_{1}D_{1}}{W_{1}}=\dfrac{M_{2}D_{2}}{W_{2}}$
$\dfrac{22\times 10}{110}=\dfrac{30\times 6}{W_{2}}$
$W_{2}=\dfrac{30\times 6\times 110}{22\times 10}$
$W_{2}=90mts$
9604.If the ratio of length and breadth of a rectangle is 4 : 7. Find the length while its breadth is
77cm
77cm
22 cm
33 cm
44 cm
55 cm
Explanation:
Breadth = 77cm
The ratio of length to breadth is 4:7
Breadth = 7 parts
7parts = 77cm
1part =$ \dfrac{77}{7}cm$=11cm
length = 4 parts
4parts =$ 4 \times 11 cm $= 44cm
Length of the rectangle = 44cm.
Breadth = 77cm
The ratio of length to breadth is 4:7
Breadth = 7 parts
7parts = 77cm
1part =$ \dfrac{77}{7}cm$=11cm
length = 4 parts
4parts =$ 4 \times 11 cm $= 44cm
Length of the rectangle = 44cm.
9606.A room is 5 m 40 cm long and 4 m 50 cm broad. Its Area is
23.4 $m^{2}$
24.3 $m^{2}$
25 $m^{2}$
98.01 $m^{2}$
Explanation:
convert cm into meter 40 cm=0.4m
50 cm=0.5m [1m=100cm]
then 5 m 40cm becomes 5.4m
likewise 4m 50 cm becomes 4.5m
then Area=l $\times$ b
=5.4 $\times 4.5$
=$24.3m^2$
convert cm into meter 40 cm=0.4m
50 cm=0.5m [1m=100cm]
then 5 m 40cm becomes 5.4m
likewise 4m 50 cm becomes 4.5m
then Area=l $\times$ b
=5.4 $\times 4.5$
=$24.3m^2$
9608.Simplify 5$\dfrac{1}{4}$ + 4$\dfrac{3}{4}$ + 7$\dfrac{5}{8}$ + 6$\dfrac{7}{8} \div$ 11$\dfrac{11}{13}$
$\dfrac{98}{47}$
$\dfrac{108}{49}$
$\dfrac{98}{45}$
$\dfrac{96}{47}$
Explanation:
convert mixed fractions into improper fractions we get
=($\dfrac{21}{4}+\dfrac{19}{4}+\dfrac{61}{8}+\dfrac{55}{8}) \div \dfrac{47}{4}$
=($\dfrac{42+38+61+55}{8})\times \dfrac{4}{47}$
=$\dfrac{196}{8} \times \dfrac{4}{47}$ by cancellation we get
=$\dfrac{98}{47}$
convert mixed fractions into improper fractions we get
=($\dfrac{21}{4}+\dfrac{19}{4}+\dfrac{61}{8}+\dfrac{55}{8}) \div \dfrac{47}{4}$
=($\dfrac{42+38+61+55}{8})\times \dfrac{4}{47}$
=$\dfrac{196}{8} \times \dfrac{4}{47}$ by cancellation we get
=$\dfrac{98}{47}$
9610.Find the rate of interest at which, a sum of money becomes $\dfrac{9}{4}$ times in 2 years.
69$\frac{1}{2}$%
67$\frac{1}{2}$%
62$\frac{1}{2}$%
61$\frac{1}{2}$%
Explanation:
Principal = P
Amount = $\dfrac{9p}{4}$
S.I. =$\dfrac{9p}{4}-P$
=$\dfrac{9p-4p}{4}$
=$\dfrac{5p}{4}$
Formula R=$\dfrac{(S.I×100)}{(P×T)}$
=$\dfrac{(5 \times p \times 100)}{(4×p×2)}$
= $\dfrac{125}{2}$
=62 $\dfrac {1}{2}$%
Principal = P
Amount = $\dfrac{9p}{4}$
S.I. =$\dfrac{9p}{4}-P$
=$\dfrac{9p-4p}{4}$
=$\dfrac{5p}{4}$
Formula R=$\dfrac{(S.I×100)}{(P×T)}$
=$\dfrac{(5 \times p \times 100)}{(4×p×2)}$
= $\dfrac{125}{2}$
=62 $\dfrac {1}{2}$%
9612.The breadth, height and volume of a cuboid are 10 cm, 11 cm and 3080$cm^{3}$ respectively.
Find the length of the cuboid.
Find the length of the cuboid.
21 cm
28 cm
24 cm
30 cm
Explanation:
volume of cuboid$=length \times breadth \times height$
Given,breadth=10cm
height=11cm
volume$=3080 cm^3.$
therefore,3080$=l \times 10 \times 11$
l=$\dfrac {3080}{10 \times 11}$
l=$\dfrac {3080}{110}$
l$=28cm ^ 3$
volume of cuboid$=length \times breadth \times height$
Given,breadth=10cm
height=11cm
volume$=3080 cm^3.$
therefore,3080$=l \times 10 \times 11$
l=$\dfrac {3080}{10 \times 11}$
l=$\dfrac {3080}{110}$
l$=28cm ^ 3$
9616.A man bought an old bicycle for Rs. 1,500. He spends Rs. 500 on its repair and sells it for
Rs. 1,800. Find the percentage of his loss.
Rs. 1,800. Find the percentage of his loss.
10%
15%
20%
5%
Explanation:
Cost Price C.P=Rs.1,500
RepairingPrice=Rs.5,00
Total NewCostPrice NC.P=Rs.2,000
SellingPrice S.P=Rs.1,800
Formula:Loss%=$\dfrac{Loss\times 100}{NC.P}$
=$\dfrac{200 \times 100}{2000}$
=$\dfrac{20000}{2000}$
=10%
Cost Price C.P=Rs.1,500
RepairingPrice=Rs.5,00
Total NewCostPrice NC.P=Rs.2,000
SellingPrice S.P=Rs.1,800
Formula:Loss%=$\dfrac{Loss\times 100}{NC.P}$
=$\dfrac{200 \times 100}{2000}$
=$\dfrac{20000}{2000}$
=10%
9618.Find the LCM of $a^{3}b^{4}$,a$b^{5}$ and $a^{2}b^{7}$
$a^{7}b^{3}$
$a^{3}b^{7}$
$a^{2}b^{5}$
a$b^{5}$
Explanation:
First,find the highest power of each element.
There are two elements a and b,and their highest power are
Highest power of a=3
highest power of b=7
therefore,LCM$=a^3 b^7$
First,find the highest power of each element.
There are two elements a and b,and their highest power are
Highest power of a=3
highest power of b=7
therefore,LCM$=a^3 b^7$
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