Given, in ΔABC, D is the midpoint of AB such that AD=DB.
A line parallel to BC intersects AC at E as shown in above figure such that DE || BC.
We have to prove that E is the mid point of AC.
Since, D is the mid-point of AB.
∴ AD=DB
$\dfrac{AD}{DB}$ = 1 …………………………. (i)
In ΔABC, DE || BC,
By using Basic Proportionality Theorem,
Therefore,$\dfrac{AD}{DB} = \dfrac{AE}{EC}$
From equation (i), we can write,
1 = $\dfrac{AE}{EC}$
∴ AE = EC
Hence, proved, E is the midpoint of AC.