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Question 10 A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?
Solution:

Given, a guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end

Let AB be the pole and AC be the wire

By Pythagoras theorem,

$AC^2 = AB^2 + BC^2$

$24^2 = 18^2 + BC^2$

$BC^2$ = 576 – 324

$BC^2$ = 252

BC = $6\sqrt{7}m$

Therefore, the distance from the base is $6\sqrt{7}$m

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